11p^2=-4p+8

Solution for 11p^2=-4p+8 equation:

11p^2=-4p+8

We move all terms to the left:

11p^2-(-4p+8)=0

We get rid of parentheses

11p^2+4p-8=0

a = 11; b = 4; c = -8;
Δ = b2-4ac
Δ = 42-4·11·(-8)
Δ = 368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{368}=\sqrt{16*23}=\sqrt{16}*\sqrt{23}=4\sqrt{23}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{23}}{2*11}=\frac{-4-4\sqrt{23}}{22}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{23}}{2*11}=\frac{-4+4\sqrt{23}}{22}
$